Binomial Theorem for Positive Integral Index

IMPORTANT

Binomial Theorem for Positive Integral Index: Overview

This topic covers concepts, such as, Finding Rational Terms in the Expansion of (a+b)^n, Finding Remainder Using Binomial Theorem, Problems Related to Binomial Expansion (Sqrt(a) + b)^n & Sum of Coefficients in Binomial Expansion etc.

Important Questions on Binomial Theorem for Positive Integral Index

HARD
IMPORTANT

Sum of the series r=010-1rCr1013r+8r32r is

EASY
IMPORTANT

If C0, C1, C2, ..., Cn are the binomial coefficients in the expansion of 1+xn, then prove that C0-C12+C22-C322+....+n+1 terms equal to 1-12n.

HARD
IMPORTANT

Let the coefficient of x1009 in the polynomial equation Px=r=01009x+Cr2019 is  in the form mn and sum of divisors of n is the product of numbers a and b where, a is composite number and b is a three-digit prime number, then

HARD
IMPORTANT

If 1+xn=C0+C1x+C2x2+...+Cnxn, then k=1nk2Ck=

HARD
IMPORTANT

Let p=r=12021-1r-1Cr20212r+1-1 and q=r=12r-1202122022r, then the value of p+q is

HARD
IMPORTANT

The equation a8x8+a7x7+a6x6++a0=0 has all roots positive and real and a8=1,a7=-4 and a0=128, then the value of a2a6a4 is equal to ______

MEDIUM
IMPORTANT

The remainder obtained when (2109)360-(1396)333 is divided by 7 is

HARD
IMPORTANT

Values of x for which the sixth term of the expansion of E=3log39|x-2|+7(1/5)log7(4)·3|x-2|-97 is 567, are

MEDIUM
IMPORTANT

Let n digit number is formed using digits from the set ={2,3,4} such that no two consecutive digits are 2 . Let an represents number of such numbers which ends with 2,bn represents number of such numbers which ends with 3 and cn represents number of such numbers which ends with 4. Then which of the following is/are correct?

EASY
IMPORTANT

The value of r=0ns=0n  nCs. sCr (where rs) is:

HARD
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The larger of 9950+10050 and 10150 is....

MEDIUM
IMPORTANT

Sum of the last 30 coefficients of powers of x in the binomial expansion of 1+x59 is

MEDIUM
IMPORTANT

If the digits at ten's and hundred's places in 112016 are x and y respectively, then the ordered pair x,y is equal to

HARD
IMPORTANT

For a positive integer n, if the mean of the binomial coefficients in the expansion of a+b2n-3 is 16, then n is equal to

MEDIUM
IMPORTANT

The sum of the series S=119!+13!·17!+15!·15!+10 terms is equal to

HARD
IMPORTANT

If A and B are the sum of the odd terms and even terms respectively in the expansion of x+an, then prove that A2-B2=x2-a2n and 4AB=x+a2n-x-a2n.

HARD
IMPORTANT

If a1,a2,a3,a4 are coefficients of the four consecutive terms in the expansion of 1+xn, then prove that a1a1+a2+a3a3+a4=2a2a2+a3.

HARD
IMPORTANT

Show that 3n-n1!3n-1+nn-12!3n-2- ....+(-1)n=C0n+C1n+C2n+.... +Cnn.

HARD
IMPORTANT

Show that 2m-m1!2m-1+mm-12!2m-2- ....+(-1)m=1.

HARD
IMPORTANT

If the coefficients of the 2nd, 3rd, 4th terms in the expansion of 1+x2n are in the A.P. Show that 2n2-9n+7=0.